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10^3-x^2-15x-6=0
We add all the numbers together, and all the variables
-1x^2-15x+994=0
a = -1; b = -15; c = +994;
Δ = b2-4ac
Δ = -152-4·(-1)·994
Δ = 4201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{4201}}{2*-1}=\frac{15-\sqrt{4201}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{4201}}{2*-1}=\frac{15+\sqrt{4201}}{-2} $
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